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Given that
[tex]\frac{8-3\sqrt{2} }{2} = a+b\sqrt{2}[/tex]
Find a and b

Sagot :

Answer:

a = 4, b = - [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

Given

[tex]\frac{8-3\sqrt{2} }{2}[/tex] = a + b[tex]\sqrt{2}[/tex] ( multiply both sides by 2 to clear the fraction )

8 - 3[tex]\sqrt{2}[/tex] = 2a + 2b[tex]\sqrt{2}[/tex]

For the 2 sides to be equal , then

2a = 8 ( divide both sides by 2 )

a = 4

and

2b = - 3 ( divide both sides by - 2 )

b = - [tex]\frac{3}{2}[/tex]

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