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Answer: The percentage composition of carbon and hydrogen in the compound are 64.4 % and 10.9 % respectively
Explanation:
Mass of [tex]CO_2[/tex] = 8.03 g
Mass of [tex]H_2O[/tex]= 3.34 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 8.03 g of carbon dioxide, =[tex]\frac{12}{44}\times 8.03=2.19g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 3.34 g of water, =[tex]\frac{2}{18}\times 3.34=0.371g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (3.4) - (2.19+0.371) = 0.839 g
percent composition of C =[tex] \frac{\text{mass of C}}{\text{ Total mass}}\times 100= \frac{2.19}{3.4}\times 1000=64.4\%[/tex]
percent composition of H =[tex] \frac{\text{mass of H}}{\text{ Total mass}}\times 100= \frac{0.371}{3.4}\times 1000=10.9\%[/tex]
Thus the percentage composition of carbon and hydrogen in the compound are 64.4 % and 10.9 % respectively
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