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Sagot :
Answer:
[tex]V_2=8L[/tex]
Explanation:
Hello there!
In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:
[tex]\frac{V_1}{n_1}=\frac{V_2}{n_2}[/tex]
Which can be solved for the final volume, V2, as shown below:
[tex]V_2=\frac{V_1n_2}{n_1}[/tex]
Thus, by plugging in the given data, we obtain:
[tex]V_2=\frac{4L*(0.250mol+0.250mol)}{0.250mol}\\\\V_2=8L[/tex]
Regards!
The final total volume of gas is equal to 8 Liters.
Given the following data:
- Initial volume = 4 Liters.
- Initial temperature = 298 K.
- Initial pressure = 2 atm.
- Initial volume = 0.250 mol.
- Final volume = 0.250 mol.
To determine the final total volume of gas, we would apply the Avogadro's equation for an ideal gas:
How to calculate the final total volume.
At constant temperature and pressure, Avogadro's equation for an ideal gas is given by this formula:
[tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]
For the final total moles:
[tex]n_2=n_1+n_1\\\\n_2 = 0.250+0.250\\\\n_2=0.50\;mol[/tex]
Making [tex]V_2[/tex] the subject of formula, we have:
[tex]V_2 = \frac{V_1n_2}{n_1}[/tex]
Substituting the given parameters into the formula, we have;
[tex]V_2 = \frac{4 \times 0.5}{0.25}[/tex]
Final total volume = 8 Liters.
Read more on ideal gas here: brainly.com/question/3173452
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