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Calculate the molarity of each aqueous solution with the given amount of Nacl58.44 and final volume. A .3.30 in 0.340L,6.00mol in 550ml,0.0160mol in 9.00ml

Sagot :

Answer:

For A: The molarity is the solution 9.706 M

For B: The molarity of the solution is 10.91 M.

For C: The molarity of the solution is 1.78 M.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}}{\text{Volume of solution (L)}}[/tex]                 ......(1)

For A:

Number of moles = 3.30 moles

Volume of solution = 0.340 L

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{3.30 mol}{0.340 L}=9.706 mol/L[/tex]

For B:

Number of moles = 6.00 moles

Volume of solution = 550 mL = 0.550 L        (Conversion factor: 1 L = 1000 mL)

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{6.00 mol}{0.550 L}=10.91 mol/L[/tex]

For C:

Number of moles = 0.0160 moles

Volume of solution = 9.00 mL = 0.009 L

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{0.0160 mol}{0.009 L}=1.78 mol/L[/tex]