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N2 + H2 --> NH3 (unbalanced) How many moles of NH3 are produced when 6.3 moles of H2 gas react with N2 gas?

Sagot :

Answer:

4.2 mol NH3

Explanation:

First, balance your reaction.

N2 + 3H2 --> 2NH3

Multiply 6.3 mol H2 by the mole ratio of 2 mol NH3 for every 3 mol H2 to get moles of NH3 produced.

6.3 mol H2 • (2 mol NH3 / 3 mol H2) = 4.2 mol NH3

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