Join the conversation on IDNLearn.com and get the answers you seek from experts. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.
Answer:
The 99% confidence level (-0.741, -0.659).
Step-by-step explanation:
The average body mass index (BMI) in a sample of 1559 men was 30.4, with a standard deviation of 0.6.
The average BMI in a sample of 1924 women was 31.1 with a standard deviation of 0.2.
Find a 99% confidence interval for the difference between the mean weights..
The formula for 99% Confidence Interval for difference between the mean weights =
μ is the population mean, and σ is the population standard deviation.
μ1 - μ2 ± z × √σ²1/n1 + σ²2/n2
The z score for 99% confidence interval = 2.576
30.4 - 31.1 ± 2.576 × √0.6²/1559 + 0.2²/1924
-0.7 ± 2.576 × √0.36/1559 + 0.04/1924
-0.7 ± 2.576 × √0.0002309173 + 0.00002079
-0.7 ± 2.576 ×√0.0002517073
-0.7 ± 2.576 × 0.015865286
-0.7 ± 0.04086897674
Hence, the 99% Confidence Interval is
-0.7 - 0.04086897674
= -0.74086897674
≈ -0.741
-0.7 + 0.04086897674
=-0.65913102326
≈ -0.659
Therefore, the 99% confidence level (-0.741, -0.659).