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Given a ≠ ± b and (a^2-b^2) / (a+b)=12 find a-b.
(I will give brainliest for helpful answers. Please don't put a link in the answer box.)

Sagot :

Peacelovingidn

Answer:

[tex] \sqrt{12a \: + \: 12b \: - \: 2ab \: + \: 2b {}^{2} } [/tex]

Step-by-step explanation:

(a²-b²) / (a+b) = 12

a² - b² = 12(a+b)

(a-b)² + 2ab - 2b² = 12a + 12b

(a-b)² = 12a + 12b - 2ab + 2b²

a - b =

[tex] \sqrt{12a \: + 12b \: - 2ab \: + \: 2b {}^{2} } [/tex]

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