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Abc is a right angle decomposed into 2 non overlapping angles. Abd and dbc. What kind of angle is dbc

Sagot :

Answer:

The answer is "[tex]m \angle ABD = 45^{\circ} \ \ and \ \ m \angle DBC = 45^{\circ}\\\\[/tex]"

Step-by-step explanation:

In this question, the adjacent angles aren't overlapping, and that they have the shared widely and have the common side. There ABC does have the correct angle, which includes two not overlapping ABD and DBC angles with such a joint B vertex and BD lines. Now it is constructed. Thus both angles are not overlapping:  

[tex]m \angle ABD = 45^{\circ}\\\\m \angle DBC = 45^{\circ}\\\\or \ \ \text{the angles will may be} \\\\m \angle ABD = 35^{\circ}\\\\m \angle DBC = 55^{\circ}\\\\[/tex]

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