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Sagot :
Answer: See explanation
Explanation:
The remainder of the question:
a). The optimal run size
b) The number of runs per year
c) The length (in days) of a run.
From the question,
p = 5000
u = 250 hotdogs per day
D = 250 × 300 = 75000 hotdogs/year
S = $66
H = 45 cents = $0.45
a. The optimal run size
= (✓2DS/✓H)(✓p/✓-✓u)
= (✓2×75000×66/✓0.45)(✓5000/✓4750)
= 4812
b) The number of runs per year
This will be:
= D/Q
= 75000/4812
= 15.59
= 16 runs per year
c) The length (in days) of a run.
This'll be:
= 4812/5000
= 0.96
= 1 day
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