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Answer:
[tex]\boxed {\boxed {\sf 9 \ moles \ Cs}}[/tex]
Explanation:
We are given the compound: Cs₃PO₄
According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.
Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.
[tex]\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}[/tex]
We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.
[tex]3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}[/tex]
[tex]3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs[/tex]
3 moles of cesium phosphate contains 9 moles of cesium.