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.50 ml of a solution are diluted to a volume of 100 ml. The concentration of the diluted
solution is 2 M. What was the concentration of the original solution?


pls answer asap! will mark as brainly ist!!


Sagot :

Answer:

4 M

Explanation:

To answer this problem we can use the following formula:

  • V₁C₁ = V₂C₂

Where the subscript 1 refers to the volume and concentration before diluting, and 2 refers to volume and concentration after diluting.

Meaning that in this case we can write:

  • 50 mL * C₁ = 100 mL * 2 M

We can now solve for C₁:

  • C₁ = 4 M
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