IDNLearn.com: Your one-stop platform for getting reliable answers to any question. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.
Sagot :
Answer:
10 days
Step-by-step explanation:
Mogaka and Ondiso working together can do a piece of job in 6 days. Mogaka working alone takes 5 days longer than Ondiso. How many days does it take Ondiso to do the work alone?
Let us represent :
The number of days
Mogaka worked alone = x
Ondiso worked alone = y
Total days worked together = T
Mogaka and Ondiso working together can do a piece of job in 6 days.
Hence,
1/x + 1/y = 1/T
Mogaka working alone takes 5 days longer than Ondiso.
x = y + 5
Therefore:
1/y + 5 + 1/y = 1/6
Multiply all through by (y+5)(y)
= y + y + 5 = (y+5)(y)/6
= 2y + 5/1 = (y+5)(y)/6
Cross Multiply
6( 2y + 5) = (y+5)(y)
12y + 30 = y² + 5y
= y² + 5y - 12y - 30 = 0
= y² - 7y - 30 = 0
Factorise
= y² +3y - 10y - 30 = 0
y(y + 3) - 10(y + 3) = 0
(y + 3)(y -10)= 0
y + 3 = 0, y = -3
y - 10 = 0
y = 10 days
Note that
The number of days Ondiso worked alone = y
Hence, it takes 10 days for Ondiso to work alone
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.
