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What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)

Sagot :

Answer:

v ≈ 4.47

Explanation:

The Formula needed = KE = [tex]\frac{1}{2}[/tex] m v²

Substitute with numbers known:

2000J = [tex]\frac{1}{2}[/tex] × 200kg × v²

Simplify:

÷100       ÷100      (Divide by 100 on both sides)

2000J = 100 × v²

[tex]\frac{2000J}{100}[/tex] =  v²

20 = v²

√         √             (Square root on both sides)

√20 = √v²

4.472135955 = v (Round to whatever the question asks)

v ≈ 4.47       (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)

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