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You are presented with a gas with 74.5L and a temperature of 333K. If the temperature drops to 131K, what is the new volume?

Sagot :

SmProidn

Answer:

29.3 L

Explanation:

According to Charle's Law:

V1/T1=V2/T2

where V=Volume & T=Temperature.

On applying the formula, we get:

74.5/333=V2/131

(74.5*131)/333=V2

V2=29.3L (approx)

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