Get comprehensive solutions to your problems with IDNLearn.com. Join our community to receive prompt and reliable responses to your questions from experienced professionals.
Sagot :
Recurring decimal is decimal representation of a number whose digits are periodic and infinite. Proved algebraically that the recurring decimal 0.178 can be written as the fraction 59/330 below.
Given information;
Given number in the decimal form is [tex]0. 1 \overline 7 \overline 8[/tex]
Suppose the number is equal to the x,
[tex]x=0. 1 \overline 7 \overline 8[/tex]
Recurring decimal
Recurring decimal is decimal representation of a number whose digits are periodic and infinite.
As the number 78 is the recurring number. Thus the recurring number can be written as,
[tex]x=0.1787878.....[/tex] .......equation 1.
Suppose this is equation number 1.
Multiply the above equation with 100 both the sides,
[tex]100\times x=100\times0. 1 787878....[/tex]
[tex]100x=100\times0.1787878...[/tex]
[tex]100x=17.87878...[/tex]
Subtract the above equation from equation number 1. Thus,
[tex]\begin{aligned}\ 100x-x&=17.87878-0.1787878\\ 99x&=17.7\\ \end[/tex]
Solve for x ,
[tex]x=\dfrac{17.7}{99} [/tex]
Multiply with 10 in both numerator and denominator,
[tex]x=\dfrac{177}{990} \\ x=\dfrac{59}{330} \\[/tex]
Hence proved algebraically that the recurring decimal 0.178 can be written as the fraction 59/330
Learn more about the recurring decimal here;
https://brainly.com/question/820308
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.