Join the IDNLearn.com community and start exploring a world of knowledge today. Get timely and accurate answers to your questions from our dedicated community of experts who are here to help you.

What is the solution set of x2 – 10 = 30x?

{–220, 250}
{–250, 220}
{15 – StartRoot 235 EndRoot, 15 + StartRoot 235 EndRoot}
{–15 – StartRoot 235 EndRoot, –15 + StartRoot 235 EndRoot}


Sagot :

9514 1404 393

Answer:

  (c)  {15 -√235, 15 +√235}

Step-by-step explanation:

For solutions p and q, the trinomial is ...

  (x -p)(x -q) = x² -(p+q)x +pq

That is, the constant term (-10) must be the product of the roots, and the x-coefficient (-30) must be the opposite of their sum.

The sums of roots in the answer choices are ...

  a) 30

  b) -30

  c) 30

  d) -30

We know the sum of roots is 30, so we can eliminate choices 'b' and 'd'.

The product of the roots must be -10, eliminating choice 'a'. Thus, the only viable choice is C.

_____

The product of the roots of C is ...

  (15 -√235)(15 +√235) = 15² -235 = -10 . . . . as required

Answer:

C

Step-by-step explanation: