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Consider the derivation of the quadratic formula below. What is the missing radicand

in Step 6?

Sagot :

MrRoyalidn

Answer:

[tex]\frac{b^2 - 4ac}{4a^2}[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required:

Complete step 6

At step 5, we have:

[tex](x + \frac{b}{2a})^2 = \frac{b^2}{4a^2} - \frac{4ac}{4a^2}[/tex]

Take LCM

[tex](x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2}[/tex]

Take square roots of both sides to get step 6

[tex]x + \frac{b}{2a} = \±\sqrt{\frac{b^2 - 4ac}{4a^2}}[/tex]

Hence, the missing radicand is: [tex]\frac{b^2 - 4ac}{4a^2}[/tex]

View image MrRoyal
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