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PLEASE HELP!
Write down the Equation of the following lines:

1)parallel to y=2x-1 and passing through (1, 8)


Sagot :

Answer:

y=2x+6

Step-by-step explanation:

We use this following formula to find the equation:

[tex]y-y_{1} =m(x-x_{1} )[/tex]

Now, we substitute the values in [tex]y_{1}[/tex] and [tex]x_{1}[/tex] :

[tex]y-8=2(x-1)[/tex]

Distribute the 2 inside the parentheses:

[tex]y-8=2x-2[/tex]

Now add 8 to both sides:

[tex]y=2x+6[/tex] is your answer.

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

y=2x-1

2=slope

-1=y intercept

NOTE: parallel lines have the same slope

and we put the point (1,8) into y=mx+b with (x,y)

8=1m+b

now we put in 2 for the slope

8=1(2)+b

6=b

2=m

now insert that back into y=mx+b

y=2x+6

and that is the line that is parallel to y=2x-1 and passes through (1,8)

Hope that helps :)