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A pumpkin is thrown horizontally off of a building at a speed of 2.5 — and travels a horizontal distance of

12 m before hitting the ground. We can ignore air resistance.

What is the vertical velocity when it hits the ground

Sagot :

Answer:

Explanation:

This is a missile throwing exercise, let's find the distance

         x = v₀ₓ / t

         t = v₀ₓ / x

let's calculate

         t = 2.5 / 12

         t = 0.2083 s

as time is a scalar this is the same value for descends to the ground

         y = v_{oy} t  - 1/2 g t²    

we calculate

         v_y = 0 - 9.8 0,2083  

         v_y = - 2.04 m / s

the negative sign indicates that the speed is down

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