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Answer:
[tex]-8x + 6y = -180[/tex]
Step-by-step explanation:
Given
[tex]\frac{4}{5} x-\frac{3}{5}y=18[/tex]
[tex]8x + 12y = 11[/tex]
Required
Equivalent form of the first equation that eliminates x when added to the second
To do this, we simply make the coefficients of x to be opposite in both equations.
In the second equation, the coefficient of x is 8.
So, we need to make the coefficient of x -8, in the first equation.
[tex]\frac{4}{5} x-\frac{3}{5}y=18[/tex]
Multiply by -10
[tex]-10 * [\frac{4}{5} x-\frac{3}{5}y=18][/tex]
[tex]\frac{-40}{5} x+\frac{30}{5}y=-180[/tex]
[tex]-8x + 6y = -180[/tex]
When this is added to the first equation, the x terms becomes eliminated