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Answer:
31.3 mL
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2HCl + Ba(OH)₂ —> BaCl₂ + 2H₂O
From the balanced equation above,
The mole ratio of the acid, HCl (nₐ) = 2
The mole ratio of the base, Ba(OH)₂ (n₆) = 1
Finally, we shall determine the volume of the acid need for the reaction as follow:
Molarity of acid, HCl (Mₐ) = 0.062 M
Mole ratio of the acid, HCl (nₐ) = 2
Volume of base, Ba(OH)₂ (V₆) = 19.4 mL
Molarity of base, Ba(OH)₂ (M₆) = 0.050 M
Mole ratio of the base, Ba(OH)₂ (n₆) = 1
Volume of acid, HCl (Vₐ) =?
MₐVₐ / M₆V₆ = nₐ / n₆
0.062 × Vₐ / 0.050 × 19.4 = 2/1
0.062 × Vₐ / 0.97 = 2
Cross multiply
0.062 × Vₐ = 0.97 × 2
0.062 × Vₐ = 1.94
Divide both side by 0.062
Vₐ = 1.94 / 0.062
Vₐ = 31.3 mL
Thus, the volume of the acid needed is 31.3 mL