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Mia is working two summer jobs, making $11 per hour babysitting and making $20 per hour lifeguarding. In a given week, she can work a maximum of 15 total hours and must earn no less than $220. If x represents the number of hours babysitting and y represents the number of hours lifeguarding, write and solve a system of inequalities graphically and determine one possible solution.

Sagot :

Answer: 11x + 20y ≥ 220

x + y ≤ 15

Hope this helps

Sqdancefanidn

9514 1404 393

Answer:

  • x + y ≤ 15
  • 11x +20y ≥ 220
  • 3 hours babysitting and 11 hours lifeguarding

Step-by-step explanation:

The two inequalities represent the two relations described in the problem statement.

  x + y ≤ 15 . . . . . . . Mia works a maximum of 15 hours

  11x + 20y ≥ 220 . . . . Mia makes at least $220

These are graphed in the attachment. The solution area is the doubly-shaded area with vertices at (9, 6), (0, 11) and (0, 15). One possible solution is shown at (3, 11), which represents ...

  3 hours babysitting

  11 hours lifeguarding . . . . . . . . total 14 hours for $253

View image Sqdancefan
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