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A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is

Sagot :

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Answer:

0.02N

Explanation:

According to Newton's 3rd Law of motion, the bee exerts the same force on the bowling ball as the bowling ball exerts the force on the bee.

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We have that for the Question "A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is" it can be said that The force the bee exerts is

F=0.02N

From the question we are told

A 60kg bowling ball collides with a 0.005kg bee with a force of 0.02N. The force the bee exerts is

Generally the Newtons  equation for Motion  is mathematically given as

This law perceives two bodies who collide as having forces which are equal as the magnitudes in opposite directions

Therefore

V^2= 2as

Hence

The force the bee exerts is

F=0.02N

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https://brainly.com/question/23379286

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