Answer
let the triangle be supposed ABC
where angle BAC is 30 degree and angle ACB is 60 degree and where we know that angle ABC is right angled triangle which means angle ABC = 90 degree
the base side of triangle is 6cm which means ;
By taking angle A as reference angle
Hypotenuse = AC = x(let)
perpendicular = BC
base = AB = 6 cm
then by taking base and hypotenuse
b/h = AB/AC
or, cos (30 degree)= 6/ x
x =[tex]4\sqrt{x} 3[/tex] cm
that concluded that AC = [tex]4\sqrt{3}[/tex] cm
Now,
by phythagorous theorem,
[tex]h^{2} = p^{2} + b^{2}[/tex]
[tex]AC =\sqrt{AB^{2} + BC^{2} } AC = \sqrt{6^{2} + 4\sqrt{3} ^{2}} \\AC = 2\sqrt{21 } cm[/tex]
so, the length of side AB is 6 cm , BC is 4[tex]\sqrt{3}[/tex] cm and AC is 2[tex]\sqrt{21}[/tex] cm
Step-by-step explanation:
