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PLS SOMEONE I NEED HELP I WILL GIVE POIHTS AND I WILL MARK BRAINLIEST I WILL DO ANYTHING JUST PLS SOMEONE ANSWER ALL OF THIS I NEED THIS DONE ASAP PLS PLS PLS IM DESPERATE IM USING MY LAST POINTS ASKING THIS QUESTIONS SO PLS HELP ME

PLS SOMEONE I NEED HELP I WILL GIVE POIHTS AND I WILL MARK BRAINLIEST I WILL DO ANYTHING JUST PLS SOMEONE ANSWER ALL OF THIS I NEED THIS DONE ASAP PLS PLS PLS I class=
PLS SOMEONE I NEED HELP I WILL GIVE POIHTS AND I WILL MARK BRAINLIEST I WILL DO ANYTHING JUST PLS SOMEONE ANSWER ALL OF THIS I NEED THIS DONE ASAP PLS PLS PLS I class=
PLS SOMEONE I NEED HELP I WILL GIVE POIHTS AND I WILL MARK BRAINLIEST I WILL DO ANYTHING JUST PLS SOMEONE ANSWER ALL OF THIS I NEED THIS DONE ASAP PLS PLS PLS I class=

Sagot :

1. a) father (Rr), mother (rr)

b) from the attached file(1)

c) the possible genotypes are

  • Rr - 50%
  • rr - 50%

d) but from the information given above the only possible genotype for SpongeGerdy is Rr, because we were told that she was squarepants

e) Rr

f) from the attached file(2)

g) the possible genotypes are

  • RR - 25%
  • Rr - 50%
  • rr - 25%

h) the genotypes for squarepants are RR and Rr

therefore probability is (25 + 50)% = 75% or 3/4

i) the only genotype for roundpants is rr

therefore probability is 25% or 1/4

2. a) wilba - Ee , wilbur -EE

b) from the attached file(3)

c) the possible genotypes are

  • EE - 50%
  • Ee - 50%

d) the genotypes for round eye are EE and Ee

therefore probability is (50 + 50)% = 100% or 1

e) the only genotype for oval eye is ee

therefore probability is 0

3. a) squidward - BB . squidette - bb

b) from the attached file(4)

c) the only possible gene is Bb - 100% or 1

d) the genotypes for a light blue skin are BB and Bb

therefore probability is (0 + 100)% = 100% or 1

e) the only genotype for a light green skin is bb

therefore probability is 0

f) No, they are not. this is because they are heterozygous i.e.( they carry gene for a light green skin)

g) from the attached file(5)

h) the possible genotypes are

  • BB - 25%
  • Bb - 50%
  • bb - 25%

i) the genotypes for a light blue skin are BB and Bb

therefore probability is (25 + 50)% = 75% or 3/4

j) the only genotype for a light green skin is bb

therefore probability is 25% or 1/4

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