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The length of a rectangle is twice as long as the width. The area is 400 feet. Find the length and with of the rectangle.

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Answer:

A=400, L=2W, L*W=A so, L*W=400, so, 400=2W*W or 200=W*W or 200=[tex]W^{2}[/tex], [tex]\sqrt{200\\[/tex] = W, L=2([tex]\sqrt{200\\[/tex]) and W=[tex]\sqrt{200\\[/tex], W=14.14 and L=28.28

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