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Find n(A) for the set.
1) A = 200, 201,
202, ..., 2000)
A) n(A)= 1801
B) n(A)= 4
C) n(A)=2000

Sagot :

Ankitrraj707idn

A=200,201,202.........,2000

Here, it forms an AP with common difference 1

Let the number of terms in the set be n

[tex] T_{n} = a+(n-1)d \\\\ 2000= 200+(n-1) \\\\ 200+n-1= 2000 \\\\ => n=2000-199= 1801[/tex]

Hence,n(A)=1801

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