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can someone help to find the missing angle measurements

Can Someone Help To Find The Missing Angle Measurements class=

Sagot :

Answer:

Angle 1 = 75°

Angle 2 = 55°

Angle 3 = 55°

Angle 4 = 40°

Angle 5 = 140°

Angle 6 = 40°

Angle 7 = 75°

Angle 8 = 65°

Angle 9 = 115°

Step-by-step explanation:

1) We start with angle 2

Angle 2

Angles on a straight line = 180°

Hence,

b + 125° = 180°

b = 180° - 125°

b = 55°

Angle 2 = 55°

2)Angle 1

The sum of angles in a triangle = 180°

Hence

Let Angle 1 = a

50° + 55° + a = 180°

a = 180° - (50° + 55°)

a = 180° - 105°

a = 75°

3)Angle 3

Angle 2 and Angle 3 are vertical angles

So we use the Vertical angle theorem

This means

Angle 2 = Angle 3

Angle 2 = 55°

Hence, Angle 3 = 55°

4) Angle 4

Sum of Angles in a triangle = 180°

Let Angle 4 = d

Hence:

85° + Angle 3 + d = 180°

85° + 55° + d = 180°

d= 180° - (85° + 55°)

d = 180°- 140°

d = 40°

5)Angle 5

Angle 4 and Angle 5 are angles on a straight line

Sum of angles on a straight line = 180°

Angle 4 = 40°

Let Angle 5 = e

Hence:

40° + e = 180°

Collect like terms

e = 180° - 40°

e = 140°

6) Angle 6

Angle 4 and Angle 6 are vertical angles

Using Vertical angle theorem,

Angle 4 = Angle 6

Angle 4 = 40°

Hence, Angle 6 = 40°

7)Angle 9

Solving for Angle 9,

Sum of angles on a straight line = 180°

Angle 9 = i

i + 65° = 180°

i = 180° - 65°

i = 115°

8) Angle 8

= Angle 9 and Angle 8 are angles in a straight line

= Angle 8 = h

h + 115° = 180°

h = 180° - 115°

h = 65°

9)Angle 7

Sum of angles in a triangle = 180°

Angle 7 = g

g = 180° - (65° + Angle 6)

= 180° - (65 + 40

= 180° - 105°

= 75°

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