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A competitive cliff diver jumps into
water 81 feet below. The distance d that the diver falls
in t seconds is given by the equation d = 16t^2. How
long does it take the diver to hit the water?

Sagot :

Answer:

2.25 seconds

Step-by-step explanation

[tex]d=16t^{2}[/tex]

[tex]d=81 feet\\t=?[/tex]

Because you know what distance equals you can plug it into the equation

[tex]81=16t^{2}[/tex]

From there you can solve by dividing the 16 over and then square rooting.

[tex]\frac{81}{16}=t^{2}[/tex]

[tex]5.0625=t^{2}[/tex]

You take the square-root to get rid of [tex]t^{2}[/tex]

[tex]\sqrt{5.0625} =\sqrt{t}^{2}[/tex]

[tex]t=2.25[/tex]

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