Answered

IDNLearn.com makes it easy to find the right answers to your questions. Discover thorough and trustworthy answers from our community of knowledgeable professionals, tailored to meet your specific needs.

A 1-kg ball is 12 m above the ground, with an initial velocity = 0 m/s.

Use the following formulas
[ KE = 1/2 xm x V2]
[P.E = mxgxh] . g =9.8 m/s2
[ Mechanical energy = K.E + P.E]

A 1kg Ball Is 12 M Above The Ground With An Initial Velocity 0 Ms Use The Following Formulas KE 12 Xm X V2 PE Mxgxh G 98 Ms2 Mechanical Energy KE PE class=

Sagot :

Answer:

M = 117.6 J

Explanation:

Given that,

The mass of a ball, m = 1kg

The height of the ball, h = 12 m

At point A, its initial velocity, v = 0

The mechanical energy is the sum of kinetic and potential energy such that,

[tex]M=\dfrac{1}{2}mv^2+mgh\\\\M=0+mgh\\\\M=1\times 9.8\times 12\\\\M=117.6\ J[/tex]

So, the mechanical energy is equal to 117.6  J.

We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.