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What is an equation of the line that passes through the point -5,7 and is parallel to the line x-5y=15

Sagot :

Aayush2024idn

Answer:

Step-by-step explanation:

Let line to be found be Line 2

Given:

Line 1

x - 5y = 15

x - 15 = 5y

Therefore slope = 1/5

Line 2

Point = (-5,7)

Slope = 1/5

Therefore: 7 = (1*-5)/5 + c

=> 7 = -1 + c

=> c = 8

Therefore equation: y = x/5 + 8

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