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Looking up, Josh sees two hot air balloons in the sky as shown. He determines that the lower hot air balloon is 700 meters away, at an angle of 38 from the vertical. The higher hot air balloon is 1050 meters away, at an angle of 26 from the vertical. How much higher is the balloon on the right than the balloon on the left? Do not round any intermediate computations. Round your answer to the nearest tenth.

Sagot :

Answer:

In right angled triangle ABC

tan 26=perpendicular/base

tan26 =BC/1050

BC=1050×tan26=512.12m

again

In right angled triangle ADE

tan 38=perpendicular/base

tan38×700=DE

DE=546.9=547m

now

difference in height =547-512.12m=34.8m=35m

35 m is your answer

View image Msm555

Josh sees two hot air balloons in the sky as shown. 35m higher is the balloon on the right than the balloon on the left.

What are the trigonometric ratios?

Trigonometric ratios for a right-angled triangle are from the perspective of a particular non-right angle.

In a right-angled triangle, two such angles are there which are not right angled(not of 90 degrees).

The slanted side is called the hypotenuse.

From the considered angle, the side opposite to it is called perpendicular, and the remaining side will be called the base.

Josh sees two hot air balloons in the sky as shown.

He determines that the lower hot air balloon is 700 meters away, at an angle of 38 from the vertical.

The higher hot air balloon is 1050 meters away, at an angle of 26 from the vertical.

In right-angled triangle ABC

tan Ф = perpendicular/base

tan26 = BC/1050

BC = 1050 × tan26

BC = 512.12m

In right-angled triangle ADE

tan Ф = perpendicular/base

tan 38 = perpendicular/base

tan38 × 700 = DE

DE = 546.9

DE = 547m

The difference in height = 547 - 512.12m

                                        =34.8m

                                       = 35m

Therefore, 35m higher is the balloon on the right than the balloon on the left.

Learn more about trigonometric ratios here:

brainly.com/question/22599614

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