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Sagot :
Answer:
312.731
Explanation:
it had a long answer but im sure ur teacher wanted u to round it
hope this helps!
~goldfishareswag/brianna
:)
Iron (III) oxide= Fe2O3
1) Find the gfm (gram formula mass, the gfm is the grams per mole. So, you’re pretty much finding one mole of Fe2O3) of Fe2O3
2 Fe: 2(55.845)
3 O: 3(15.9994)
=160 gfm
2) multiply gfm by mole number
160(1 mole of Fe2O3 is 160. What are 5.6 moles?)
160 x 5.6
= 896g
1) Find the gfm (gram formula mass, the gfm is the grams per mole. So, you’re pretty much finding one mole of Fe2O3) of Fe2O3
2 Fe: 2(55.845)
3 O: 3(15.9994)
=160 gfm
2) multiply gfm by mole number
160(1 mole of Fe2O3 is 160. What are 5.6 moles?)
160 x 5.6
= 896g
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