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Answer:
Option B.
Step-by-step explanation:
We have the equation:
x^2 + 6*x - 2 = 0
Remember that:
(a*x + b)^2 = (a*x)^2 + 2*a*b*x + b^2
Because the term with x^2 has a coefficient equal to 1, then a = 1.
(x + b)^2 = x^2 + 2*b*x + b^2
The ter with x is: 6*x
then:
2*b*x = 6*X
2*b = 6
b = 6/2 = 3
we have:
(x + 3)^2 = x^2 + 6*x + 9
Now, our equation is:
x^2 + 6*x - 2 = 0
Now we can add the term (11 - 11) = 0
x^2 + 6*x - 2 + (11 - 11) = 0
x^2 + 6*x - 2 + 11 - 11 = 0
x^2 + 6*x + (11 - 2) - 11 = 0
x^2 + 6*x + 9 - 11 = 0
And we know that:
x^2 + 6*x + 9 = (x + 3)^2
Then we can rewrite our equation as:
(x + 3)^2 - 11 = 0
Then the correct option is B.
Answer:
See below attachment
Step-by-step explanation:
A p E x
