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A cylinder of compressed gas rolls off a boat and falls to the bottom of a lake. Eventually it rusts and the gas bubbles to the surface. A chemist collects a sample of the gas with the idea of trying to identify the gas. The wet gas collected occupies a volume of 283 mL at a pressure of 745 torr and temperature of 28.0oC. The vapor pressure of water at 28.0oC is 0.0372 atm. 1. Calculate the volume (L) that the gas occupies after it is dried (the water vapor removed) and stored at STP. Tries 0/99 The mass of the dry gas is 905 mg. A fragment of the tank indicates that the gas is a monoatomic element. 2. Write out the full name of the gas.

Sagot :

Pstnonsonjokuidn

Answer:

See explanation

Explanation:

From the information given;

We convert the pressure from torr to atm as follows;

745 torr * 1 atm/760 torr = 0.98 atm

Initial pressure P1 =  0.98 atm - 0.0372 atm = 0.9428 atm

Initial volume V1=  283 mL

Initial temperature T1 = 28.0oC + 273 = 301 K

Final volume V2 = ??

Final Temperature T2 = 273 K

Final pressure P2 = 1 atm

From the general gas equation;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 0.9428 * 283 * 273/1 *  301

V2 = 241.99 mL or 0.24 L

If 1 mole of gas occupies 22.4 L

x moles of gas occupies 0.24 L

x =  1 mole  * 0.24 L/ 22.4 L

x = 0.0107 moles

But number of moles = mass/molar mass

molar mass = mass/number of moles

molar mass = 905 * 10^-3g/0.0107 moles

molar mass = 84 g/mol

The monoatomic gas is Krypton

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