Answer-
When the height is doubled, the volume of the cone also gets doubled.
Solution-
Volume of a cone is given by,
[tex]V=\dfrac{\pi \times r^2\times h}{3}[/tex]
Where,
V = Volume,
r = radius of the base,
h = height of the cone.
Let, height at first be x, then volume would be,
[tex]V_1=\dfrac{\pi \times r^2\times x}{3}[/tex]
As the height is doubled, so height = 2x, then volume would be,
[tex]V_2=\dfrac{\pi \times r^2\times 2x}{3}\\\\=2\times \dfrac{\pi \times r^2\times x}{3}\\\\=2\times V_1[/tex]
Therefore, when the height is doubled, the volume of the cone also gets doubled.
