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How do I figure this problem 1/5 > d + 4/5

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Luanaidn
[tex]\frac{1}{5}>d+\frac{4}{5}\ \ \ \ \ \ \ \ |subtract\ \frac{4}{5}\\\\\frac{1}{5}-\frac{4}{5}>d\\\\d<-\frac{3}{5}\\\\d\in(-\infty,-\frac{3}{5})[/tex]
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