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What are equivalent expressions for 6(y-1) and 64x+80

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Iloveonedirectionidn
To find equivalent expressions, distribute the first one and factor the second one.

[tex]6(y-1) \\ (6*y)+(6*-1) \\ 6y-6 \\ \\ 6(y-1)=6y-6 \\ \\ 64x+80 \\ 16( \frac{64}{16}x+ \frac{80}{16}) \\ 16(4x+5) \\ \\ 64x+80=16(4x+5)[/tex]
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