IDNLearn.com is committed to providing high-quality answers to your questions. Explore a wide array of topics and find reliable answers from our experienced community members.
Sagot :
You simply have to take the linear equation form (ax + by = c) and solve for y. So you get:
by = c - ax
y = c/b - ax/b
Since c/b will be a constant, you can replace it with any variable (i.e. b), and so that represents the y-intercept and a/b will also be a constant, so that can also be replaced by any variable (i.e. m), and it represents the slope.
by = c - ax
y = c/b - ax/b
Since c/b will be a constant, you can replace it with any variable (i.e. b), and so that represents the y-intercept and a/b will also be a constant, so that can also be replaced by any variable (i.e. m), and it represents the slope.
Arithmetic operations can be used to change linear equations in form ax+by=c to y=mx+b form and vice versa and this can be determined by simple subtraction and division operation.
Given :
ax + by = c
y = mx + c
The following steps can be used to change the linear equation in form (ax+by=c) to (y=mx+b) form:
Step 1 - Write the equation.
ax + by = c
Step 2 - Subtract ax from both the sides in the above equation.
ax + by - ax = c - ax
by = c - ax
Step 3 - Divide by 'b' from both sides in the above equation.
[tex]y = \dfrac{-a}{b}x+\dfrac{c}{b}[/tex]
By following the above steps equation (ax + by = c) can be converted into (y = mx + c).
The following steps can be used to change linear equation in form (y = mx + c) to (ax + by = c) form:
Step 1 - Write the equation.
y = mx + c
Step 2 - Subtract mx from both sides in the above equation.
y - mx = c + mx -mx
y - mx = c
By following the above steps equation (y = mx +c) can be converted into (ax + by = c).
For more information, refer to the link given below:
https://brainly.com/question/13101306
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.
