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The total force on charge q(3) is 1125 x [tex]10^{-3}[/tex] Newton
We have three charges in a straight line.
We have to find the force on charge q3 due to charge q1 and q2.
State Coulomb's law.
The force between two point charges is directly proportional to the product of the magnitude of two point charges and inversely proportional to the square of the distance between them. Mathematically-
[tex]F = \frac{1}{4\pi\epsilon_{o}}{\frac{qQ}{r^{2} } } }[/tex]
We have -
[tex]q_{1} =q_{2} =q_{3} = -5 \times 10^{-6} C[/tex]
The distance between -
[tex]q_{1}\;and\;q_{2} = q_{2} \;and\;q{3}[/tex] = 0.5 m
Now, Force on charge q(3) due to charge q(1) -
F(1 → 3) = [tex]\frac{1}{4\pi\epsilon_{o}}{\frac{5\times 10^{-6} \times 5\times 10^{-6} }{1^{2} } } } = 9\times 10^{9} \times 25 \times 10^{-12} = 225\times 10^{-3}[/tex] N (repelling force)
Force on charge q(3) due to charge q(2) can be calculate similarly as -
F(2 → 3) = 900 x [tex]10^{-3}[/tex] N(repelling force)
Now, both the forces are in same direction, so we can add them algebraically -
[tex]F_{net}[/tex] = F(1 → 3) + F(2 → 3) = 1125 x [tex]10^{-3}[/tex] N
Hence, the total force on charge q(3) is 1125 x [tex]10^{-3}[/tex] Newton
Hence, the wavelength of light in nano meters is 0.0177 x nm.
To solve more questions on Coulomb's law, visit the link below -
https://brainly.com/question/14110379
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