A certain lake has a volume of about 480 m³. If the total population of freshwater shrimp in the lake is 600 million, what is the population density of the shrimp in that lake?

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01-05-2021
Biology

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A certain lake has a volume of about 480 m³. If the total population of freshwater shrimp in the lake is 600 million, what is the population density of the shrimp in that lake?

Sagot :

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Samueladesida43idn Samueladesida43idn · Answer 1 · 2021-05-05T20:03:35-04:00

Answer:

1,250,000 shrimps per m³

Explanation:

Population density refers to how dense an area is per unit area/volume, and it is calculated by dividing the number of individuals in that area (population) by the area/volume of that area. That is;

Population density = population (N)/volume

According to this question, a certain lake has a volume of about 480 m³ that harbors a 600 million of freshwater shrimp. This means that;

Population density of the lake = population of shrimps ÷ volume of lake

Population density = 600,000,000 ÷ 480

Population density = 1,250,000 shrimps per m³

Sagot :

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