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Find the equilibrium point for the demand and supply functions given .....hint: find x when D(x)=S(x)

D(x)= 3500-80x
S(x)=250+10x

Sagot :

3500-80x=250+10x

3500=250+90x
3250=90x
3250/90
X=36.1 repeating
Konrad509idn
[tex]3500-80x=250+10x\\ -90x=-3250\\ x=\frac{325}{9}\approx36.1[/tex]
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