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Shown below is a 10 kg block being pushed by a horizontal force F of magnitude 200N. The coefficient of kinetic friction between the two surface is 0.50. Find the acceleration of the block.

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Answer:

15.1 m/s²

Explanation:

Step 1: Calculate the force exerted by the friction

Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.

Ff = μ × m × g

where,

μ: coefficient of kinetic friction

m: mass of the block

g: gravity

Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N

Step 2: Calculate the resulting force

The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.

R = F - Ff = R = 200 N - 49 N = 151 N

Step 3: Calculate the acceleration of the block

We will use Newton's second law of motion.

R = m × a

a = R/m

a = 151 N/10 kg = 15.1 m/s²

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