Answered

IDNLearn.com offers a comprehensive solution for all your question and answer needs. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

the sum of 2 numbers is 56.twice the smaller number exceeds one-half the larger number by 22.find the numbers

Sagot :

Sqdancefanidn

9514 1404 393Answer:

  20, 36

Step-by-step explanation:

Let x and y represent the smaller and larger numbers, respectively. The given relations let us write two equations:

  x + y = 56 . . . . . . the sum of the two numbers is 56

  2x -y/2 = 22 . . . . twice the smaller exceeds half the larger by 22

We can solve this by multiplying the second equation by 2 and adding the first.

  2(2x -y/2) +(x +y) = 2(22) +56

  5x = 100 . . . . . . simplify

  x = 20

  y = 56 -20 = 36

The two numbers are 20 and 36.

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.