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A 3mL sample of a 200 Molar solution is left open on a lab
counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?


Sagot :

Answer: New volume of the solution is 100 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 3 mL,     [tex]M_{1}[/tex] = 200 M

[tex]M_{2}[/tex] = 6 M,     [tex]V_2[/tex] = ?

Formula used to calculate the new volume of solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]

Thus, we can conclude that new volume of the solution is 100 mL.