Connect with experts and get insightful answers on IDNLearn.com. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.
Sagot :
Answer:
18.368 Liters
Explanation:
Given that balanced Acetone oxidation,
= C3H6O + 4O2 = 3CO2 + 3H2O
lets assume volume of acetone = 1 liter
mass of acetone = 50 mg
number of moles present = (5*10^-3)g / ( 58.08 ) = 0.0000861 mol
Given that : I mol of ( acetone ) = 4 mol of oxygen
∴0.0000861 mol of acetone = 0.0003444 mol of oxygen
also note that the ratio of air to oxygen is
0.21 mol of oxygen = 1 mol of air
∴ 0.0003444 mol of oxygen = 0.00164 mol of air (0.0003444 / 0.21 )
note : 1 mol at STP = 22.4 L (at STP = Temperature = O°C
Finally the theoretically oxygen demand in liters of air for a 50 mg/L of acetone to decompose
Given that Acetone decompose/degrade completely between 500°C - 600°
we will take 500° for the sake of this calculation
The oxygen demand in liters will be
= 22.4 * 0.00164 * 500 = 18.368 Liters
The theoretical oxygen demand in liters of air for a 50 mg / L acetone solution, to decompose completely is 18.368 Liters.
How we calculate moles?
Moles of any substance will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction is:
CH₃COCH₃ + 4O₂ → 3CO₂ + 3H₂O
Given mass of acetone = 50mg = 0.05g
Moles of acetone = 0.05g / 58.08g/mol = 0.0000861 mole
From the stoichiometry of the reaction, it is clear that:
1 mole of CH₃COCH₃ = 4 moles of O₂
0.0000861 mole of CH₃COCH₃ = 4×0.0000861=0.0003444 moles of O₂
We know that ratio of air is:
0.21 mole of oxygen present = in 1 mole of air
0.0003444 mole of oxygen present = in 0.0003444/0.21=0.00164 mole of air
At STP 1 mole of gas is present in 22.4 Liter.
Degradation of acetone takes place in 500°C - 600°C.
Theoretical oxygen demand = 22.4×0.00164×500 = 18.368 Liters
Hence, theoretical oxygen demand is 18.368 Liters.
To know more about theoretical oxygen demand, visit the below link:
https://brainly.com/question/13251445
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.
