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Answer:
10.5 L of O₂.
Explanation:
We'll begin by calculating the number of mole in 90 g of C₂H₆. This can be obtained as follow:
Molar mass of C₂H₆ = (12×2) + (6×1)
= 24 + 6
= 30 g/mol
Mass of C₂H₆ = 90 g
Mole of C₂H₆ =?
Mole = mass / molar mass
Mole of C₂H₆ = 90 / 30
Mole of C₂H₆ = 3 moles.
Finally, we shall determine the volume of O₂ required. This is illustrated:
2C₂H₆ + 7O₂ —> 4CO₂ + 6H₂O
From the balanced equation above, we can say that:
2 L of C₂H₆ required 7 L of O₂.
Therefore, 3 L of C₂H₆ will require
= (3 × 7)/ 2 = 10.5 L of O₂.
Thus, 10.5 L of O₂ is required for the reaction.