Answered

Experience the convenience of getting your questions answered at IDNLearn.com. Ask your questions and get detailed, reliable answers from our community of knowledgeable experts.

A system releases 7.9kj of heat while 6.5kj work is done on it. Calculate

Sagot :

Stigawithfunidn

Question:

A system releases 7.9kj of heat while 6.5kj work is done on it. Calculate the total change in internal energy during these operations in kJ.

Answer:

14.4kJ

Explanation:

The first law of thermodynamics which states that the total change in internal energy (ΔU) of a system is the sum of the total heat (Q) released by the system to its surroundings and the total work done (W) on the system by its surrounding, can be expressed mathematically as follows:

ΔU = Q + W      -------------------(i)

From the question;

Q = 7.9kJ

W = 6.5kJ

Substitute these values into equation(i) as follows;

ΔU = 7.9kJ + 6.5kJ

ΔU = 14.4kJ

Therefore, the change in internal energy is 14.4kJ

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.