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What is the equation in stope intercepe form of the line that passes through the points (-4.47) and (2.-16)​

What Is The Equation In Stope Intercepe Form Of The Line That Passes Through The Points 447 And 216 class=

Sagot :

MrRoyalidn

Answer:

[tex]y = -\frac{21}{2}x+5[/tex]

Step-by-step explanation:

Given

[tex](x_1,y_1) = (-4,47)[/tex]

[tex](x_2,y_2) = (2,-16)[/tex]

Required

The equation in slope intercept

First, calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex](x_1,y_1) = (-4,47)[/tex]

[tex](x_2,y_2) = (2,-16)[/tex]

So:

[tex]m = \frac{-16 - 47}{2 - -4}[/tex]

[tex]m = \frac{-63}{6}[/tex]

Simplify

[tex]m = -\frac{21}{2}[/tex]

So, the equation is calculated as:

[tex]y = m(x - x_1) + y_2[/tex]

This gives:

[tex]y = -\frac{21}{2}(x - -4) + 47[/tex]

[tex]y = -\frac{21}{2}(x+4) + 47[/tex]

Open bracket

[tex]y = -\frac{21}{2}x-42 + 47[/tex]

[tex]y = -\frac{21}{2}x+5[/tex]

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