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Answer: No real solution
Step-by-step explanation:
Given
For the quadratic equation
[tex]ax^2+bx+c=0[/tex]
It is given that [tex]b^2-4ac<0[/tex]
[tex]D=b^2-4ac[/tex]
If [tex]D=0[/tex] roots are real and equal
If [tex]D>0[/tex] roots are real and distinct
If [tex]D<0[/tex] roots are imaginary
In this case, [tex]D<0[/tex]
So, there is no real solution for the given quadratic equation.